Optimal. Leaf size=196 \[ \frac {i a x}{c^3 d}-\frac {b x}{2 c^3 d}+\frac {i b x^2}{6 c^2 d}+\frac {b \text {ArcTan}(c x)}{2 c^4 d}+\frac {i b x \text {ArcTan}(c x)}{c^3 d}+\frac {x^2 (a+b \text {ArcTan}(c x))}{2 c^2 d}-\frac {i x^3 (a+b \text {ArcTan}(c x))}{3 c d}+\frac {(a+b \text {ArcTan}(c x)) \log \left (\frac {2}{1+i c x}\right )}{c^4 d}-\frac {2 i b \log \left (1+c^2 x^2\right )}{3 c^4 d}+\frac {i b \text {PolyLog}\left (2,1-\frac {2}{1+i c x}\right )}{2 c^4 d} \]
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Rubi [A]
time = 0.22, antiderivative size = 196, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 11, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.478, Rules used = {4986, 4946,
272, 45, 327, 209, 4930, 266, 4964, 2449, 2352} \begin {gather*} \frac {\log \left (\frac {2}{1+i c x}\right ) (a+b \text {ArcTan}(c x))}{c^4 d}+\frac {x^2 (a+b \text {ArcTan}(c x))}{2 c^2 d}-\frac {i x^3 (a+b \text {ArcTan}(c x))}{3 c d}+\frac {i a x}{c^3 d}+\frac {b \text {ArcTan}(c x)}{2 c^4 d}+\frac {i b x \text {ArcTan}(c x)}{c^3 d}+\frac {i b \text {Li}_2\left (1-\frac {2}{i c x+1}\right )}{2 c^4 d}-\frac {b x}{2 c^3 d}+\frac {i b x^2}{6 c^2 d}-\frac {2 i b \log \left (c^2 x^2+1\right )}{3 c^4 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 45
Rule 209
Rule 266
Rule 272
Rule 327
Rule 2352
Rule 2449
Rule 4930
Rule 4946
Rule 4964
Rule 4986
Rubi steps
\begin {align*} \int \frac {x^3 \left (a+b \tan ^{-1}(c x)\right )}{d+i c d x} \, dx &=\frac {i \int \frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{d+i c d x} \, dx}{c}-\frac {i \int x^2 \left (a+b \tan ^{-1}(c x)\right ) \, dx}{c d}\\ &=-\frac {i x^3 \left (a+b \tan ^{-1}(c x)\right )}{3 c d}-\frac {\int \frac {x \left (a+b \tan ^{-1}(c x)\right )}{d+i c d x} \, dx}{c^2}+\frac {(i b) \int \frac {x^3}{1+c^2 x^2} \, dx}{3 d}+\frac {\int x \left (a+b \tan ^{-1}(c x)\right ) \, dx}{c^2 d}\\ &=\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d}-\frac {i x^3 \left (a+b \tan ^{-1}(c x)\right )}{3 c d}-\frac {i \int \frac {a+b \tan ^{-1}(c x)}{d+i c d x} \, dx}{c^3}+\frac {(i b) \text {Subst}\left (\int \frac {x}{1+c^2 x} \, dx,x,x^2\right )}{6 d}+\frac {i \int \left (a+b \tan ^{-1}(c x)\right ) \, dx}{c^3 d}-\frac {b \int \frac {x^2}{1+c^2 x^2} \, dx}{2 c d}\\ &=\frac {i a x}{c^3 d}-\frac {b x}{2 c^3 d}+\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d}-\frac {i x^3 \left (a+b \tan ^{-1}(c x)\right )}{3 c d}+\frac {\left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d}+\frac {(i b) \text {Subst}\left (\int \left (\frac {1}{c^2}-\frac {1}{c^2 \left (1+c^2 x\right )}\right ) \, dx,x,x^2\right )}{6 d}+\frac {(i b) \int \tan ^{-1}(c x) \, dx}{c^3 d}+\frac {b \int \frac {1}{1+c^2 x^2} \, dx}{2 c^3 d}-\frac {b \int \frac {\log \left (\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx}{c^3 d}\\ &=\frac {i a x}{c^3 d}-\frac {b x}{2 c^3 d}+\frac {i b x^2}{6 c^2 d}+\frac {b \tan ^{-1}(c x)}{2 c^4 d}+\frac {i b x \tan ^{-1}(c x)}{c^3 d}+\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d}-\frac {i x^3 \left (a+b \tan ^{-1}(c x)\right )}{3 c d}+\frac {\left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d}-\frac {i b \log \left (1+c^2 x^2\right )}{6 c^4 d}+\frac {(i b) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+i c x}\right )}{c^4 d}-\frac {(i b) \int \frac {x}{1+c^2 x^2} \, dx}{c^2 d}\\ &=\frac {i a x}{c^3 d}-\frac {b x}{2 c^3 d}+\frac {i b x^2}{6 c^2 d}+\frac {b \tan ^{-1}(c x)}{2 c^4 d}+\frac {i b x \tan ^{-1}(c x)}{c^3 d}+\frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{2 c^2 d}-\frac {i x^3 \left (a+b \tan ^{-1}(c x)\right )}{3 c d}+\frac {\left (a+b \tan ^{-1}(c x)\right ) \log \left (\frac {2}{1+i c x}\right )}{c^4 d}-\frac {2 i b \log \left (1+c^2 x^2\right )}{3 c^4 d}+\frac {i b \text {Li}_2\left (1-\frac {2}{1+i c x}\right )}{2 c^4 d}\\ \end {align*}
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Mathematica [A]
time = 0.30, size = 166, normalized size = 0.85 \begin {gather*} -\frac {i \left (-b-6 a c x-3 i b c x+3 i a c^2 x^2-b c^2 x^2+2 a c^3 x^3+6 b \text {ArcTan}(c x)^2+\text {ArcTan}(c x) \left (6 a+b \left (3 i-6 c x+3 i c^2 x^2+2 c^3 x^3\right )+6 i b \log \left (1+e^{2 i \text {ArcTan}(c x)}\right )\right )-3 i a \log \left (1+c^2 x^2\right )+4 b \log \left (1+c^2 x^2\right )+3 b \text {PolyLog}\left (2,-e^{2 i \text {ArcTan}(c x)}\right )\right )}{6 c^4 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.16, size = 312, normalized size = 1.59
method | result | size |
derivativedivides | \(\frac {-\frac {11 i b \ln \left (c^{2} x^{2}+1\right )}{24 d}-\frac {i a \arctan \left (c x \right )}{d}+\frac {a \,c^{2} x^{2}}{2 d}-\frac {a \ln \left (c^{2} x^{2}+1\right )}{2 d}-\frac {i b \ln \left (c x -i\right )^{2}}{4 d}-\frac {5 i b \ln \left (c^{4} x^{4}+10 c^{2} x^{2}+9\right )}{48 d}+\frac {i a c x}{d}+\frac {b \arctan \left (c x \right ) c^{2} x^{2}}{2 d}-\frac {b \arctan \left (c x \right ) \ln \left (c x -i\right )}{d}+\frac {i b \,c^{2} x^{2}}{6 d}+\frac {2 i b}{3 d}-\frac {i b \arctan \left (c x \right ) c^{3} x^{3}}{3 d}-\frac {b c x}{2 d}+\frac {i b \ln \left (c x -i\right ) \ln \left (-\frac {i \left (c x +i\right )}{2}\right )}{2 d}+\frac {i b \arctan \left (c x \right ) c x}{d}+\frac {i b \dilog \left (-\frac {i \left (c x +i\right )}{2}\right )}{2 d}+\frac {11 b \arctan \left (c x \right )}{12 d}-\frac {i a \,c^{3} x^{3}}{3 d}+\frac {5 b \arctan \left (\frac {c x}{2}\right )}{24 d}-\frac {5 b \arctan \left (\frac {1}{6} c^{3} x^{3}+\frac {7}{6} c x \right )}{24 d}-\frac {5 b \arctan \left (\frac {c x}{2}-\frac {i}{2}\right )}{12 d}}{c^{4}}\) | \(312\) |
default | \(\frac {-\frac {11 i b \ln \left (c^{2} x^{2}+1\right )}{24 d}-\frac {i a \arctan \left (c x \right )}{d}+\frac {a \,c^{2} x^{2}}{2 d}-\frac {a \ln \left (c^{2} x^{2}+1\right )}{2 d}-\frac {i b \ln \left (c x -i\right )^{2}}{4 d}-\frac {5 i b \ln \left (c^{4} x^{4}+10 c^{2} x^{2}+9\right )}{48 d}+\frac {i a c x}{d}+\frac {b \arctan \left (c x \right ) c^{2} x^{2}}{2 d}-\frac {b \arctan \left (c x \right ) \ln \left (c x -i\right )}{d}+\frac {i b \,c^{2} x^{2}}{6 d}+\frac {2 i b}{3 d}-\frac {i b \arctan \left (c x \right ) c^{3} x^{3}}{3 d}-\frac {b c x}{2 d}+\frac {i b \ln \left (c x -i\right ) \ln \left (-\frac {i \left (c x +i\right )}{2}\right )}{2 d}+\frac {i b \arctan \left (c x \right ) c x}{d}+\frac {i b \dilog \left (-\frac {i \left (c x +i\right )}{2}\right )}{2 d}+\frac {11 b \arctan \left (c x \right )}{12 d}-\frac {i a \,c^{3} x^{3}}{3 d}+\frac {5 b \arctan \left (\frac {c x}{2}\right )}{24 d}-\frac {5 b \arctan \left (\frac {1}{6} c^{3} x^{3}+\frac {7}{6} c x \right )}{24 d}-\frac {5 b \arctan \left (\frac {c x}{2}-\frac {i}{2}\right )}{12 d}}{c^{4}}\) | \(312\) |
risch | \(\frac {i b \ln \left (i c x +1\right )^{2}}{4 c^{4} d}+\frac {b \arctan \left (c x \right )}{2 c^{4} d}-\frac {b \left (\frac {1}{3} c^{2} x^{3}+\frac {1}{2} i c \,x^{2}-x \right ) \ln \left (i c x +1\right )}{2 c^{3} d}+\frac {\ln \left (-i c x +1\right ) x^{3} b}{6 d c}-\frac {i a \arctan \left (c x \right )}{d \,c^{4}}-\frac {\ln \left (-i c x +1\right ) x b}{2 d \,c^{3}}-\frac {i b \ln \left (\frac {1}{2}+\frac {i c x}{2}\right ) \ln \left (-i c x +1\right )}{2 d \,c^{4}}+\frac {31 i b}{72 c^{4} d}+\frac {i a x}{c^{3} d}+\frac {i \ln \left (-i c x +1\right ) x^{2} b}{4 d \,c^{2}}-\frac {5 a}{6 d \,c^{4}}-\frac {a \ln \left (c^{2} x^{2}+1\right )}{2 d \,c^{4}}-\frac {2 i b \ln \left (c^{2} x^{2}+1\right )}{3 c^{4} d}+\frac {i b \dilog \left (\frac {1}{2}-\frac {i c x}{2}\right )}{2 d \,c^{4}}+\frac {i b \ln \left (\frac {1}{2}+\frac {i c x}{2}\right ) \ln \left (\frac {1}{2}-\frac {i c x}{2}\right )}{2 d \,c^{4}}+\frac {x^{2} a}{2 d \,c^{2}}+\frac {i b \,x^{2}}{6 c^{2} d}-\frac {i x^{3} a}{3 d c}-\frac {b x}{2 c^{3} d}\) | \(331\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \frac {i \left (\int \frac {6 i b \log {\left (i c x + 1 \right )}}{c^{2} x^{2} + 1}\, dx + \int \frac {12 a c^{4} x^{4}}{c^{2} x^{2} + 1}\, dx + \int \frac {6 b c x}{c^{2} x^{2} + 1}\, dx + \int \frac {b c^{3} x^{3}}{c^{2} x^{2} + 1}\, dx + \int \frac {12 i a c^{3} x^{3}}{c^{2} x^{2} + 1}\, dx + \int \frac {3 i b c^{2} x^{2}}{c^{2} x^{2} + 1}\, dx + \int \left (- \frac {2 i b c^{4} x^{4}}{c^{2} x^{2} + 1}\right )\, dx + \int \left (- \frac {6 b c x \log {\left (i c x + 1 \right )}}{c^{2} x^{2} + 1}\right )\, dx + \int \frac {6 b c^{3} x^{3} \log {\left (i c x + 1 \right )}}{c^{2} x^{2} + 1}\, dx + \int \left (- \frac {6 i b c^{4} x^{4} \log {\left (i c x + 1 \right )}}{c^{2} x^{2} + 1}\right )\, dx\right )}{12 c^{3} d} + \frac {\left (2 b c^{3} x^{3} + 3 i b c^{2} x^{2} - 6 b c x - 6 i b \log {\left (i c x + 1 \right )}\right ) \log {\left (- i c x + 1 \right )}}{12 c^{4} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^3\,\left (a+b\,\mathrm {atan}\left (c\,x\right )\right )}{d+c\,d\,x\,1{}\mathrm {i}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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